PLEASE ANSWER ILL MARK !!

Step-by-step explanation:
a) Use sine law:
[tex]\dfrac{g}{\sin 60} = \dfrac{17\:m}{\sin 49}[/tex]
Solving for g,
[tex]g = \left(\dfrac{\sin 60}{\sin 49}\right)(17\:m)=19.5\:m[/tex]
b) Use the cosine law here:
[tex]q^2 = (11\:\text{cm})^2 + (16\:\text{cm})^2 \\ - 2(11\:\text{cm})(16\:\text{cm})\cos 29[/tex]
Solving for q,
[tex]q = 8.3\:\text{cm}[/tex]