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The sum of four consecutive numbers is two more than three times the greatest of these numbers. Find the numbers.

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Answer:

9, 10, 11, 12

Step-by-step explanation:

Let the consecutive numbers be:

x, x+1, x+2, x+3

Greatest of the numbers will be: x + 3

x+x+1+x+2+x+3 = 3(x+3) + 2

4x + 6 = 3(x+4) + 2

4x + 6 = 3x + 12 + 2

4x + 6 = 3x + 14

Collect like terms

4x - 3x = 14 - 6

x = 8

x +1 = 8+ 1 = 9

x + 2 = 8 + 2 = 10

x + 3 = 8 + 3 = 11

x + 4 = 8 + 4 = 12

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