Complete question:
Given Q(x) = 7x − 3 and P(x) = 7x3 − 3x2 + 42x − 27, find P(x) ÷ Q(x) . (Divide using long division.)
Answer:
[tex]\frac{7x^3 \ - \ 3x^2 \ + \ 42x \ - \ 27}{7x \ - \ 3} = \ \ x^2 + 6 \ \ \frac{-9}{7x \ - \ 3}[/tex]
The quotient = x² + 6 and the remainder = - 9
Step-by-step explanation:
Given;
Q(x) = 7x − 3
P(x) = 7x³ − 3x² + 42x − 27
To divide P(x) by Q(x) using long division, we apply the following method;
x² + 6
---------------------------------
7x − 3 √ 7x³ − 3x² + 42x − 27
− (7x³ - 3x²)
-------------------------------------
42x − 27
− (42x − 18)
----------------------------------------
− 9
[tex]Therefore, \ \frac{7x^3 \ - \ 3x^2 \ + \ 42x \ - \ 27}{7x \ - \ 3} = \ \ x^2 + 6 \ \ \frac{-9}{7x \ - \ 3}[/tex]
The quotient = x² + 6 and the remainder = - 9
