Answer:
[tex]\angle ADB \cong \angle CDB[/tex]
[tex]\angle DBA \cong \angle DBC[/tex]
[tex]BD = BD[/tex]
Step-by-step explanation:
Given
[tex]\triangle ABD \cong \triangle CBD[/tex]
Required
The congruent segments by CPCTC
From the question, we have:
[tex]\angle ADB \cong \angle CDB[/tex] --- given
[tex]\angle DBA \cong \angle DBC[/tex] --- given
Both triangles share a common side (length BD);
So, we have:
[tex]BD = BD[/tex]
Hence, the congruent segments are:
[tex]\angle ADB \cong \angle CDB[/tex]
[tex]\angle DBA \cong \angle DBC[/tex]
[tex]BD = BD[/tex]
