Answer:
1,404,000 unique passwords are possible.
Step-by-step explanation:
The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this question:
2 digits from a set of 10(there are 10 possible digits, 0-9).
3 characters from a set of 26. So
[tex]P_{10,2}P_{26,3} = \frac{10!}{8!} \times \frac{26!}{23!} = 10*9*26*25*24 = 1404000[/tex]
1,404,000 unique passwords are possible.
