ZJSG09112007
contestada

Iff a projectile has a maximum range of 40 metres , find its speed of projection . ([tex]g = 10ms^-^2[/tex])
.[tex]0.5 ms^-^1\\2ms^-^1\\\\4ms^-^1\\\\20ms^-^1\\\\400ms^-^1[/tex]

Respuesta :

msm555

its speed of projection is 20 ms^(-1)

Answer:

Solution given:

maximum range=40m

u²sin90°/g=40

u²*sin90°/10=40

u²=40*10

u=[tex]\sqrt{400}=20m/s[/tex]

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