Answer:
5b^2-(5+6)b+6=0
5b^2-5b-6b+6=0
5b(b-1)-6(b-1)=0
(5b-6)(b-1)=0
either
(5b-1)=0
5b=1
b=1/5
or
b-1=0
b=1
Step-by-step explanation:
firstly find out the mid term factor i e in above qn 11 should be break down so that its multiple should be coefficient of b and constant and additiqn should be equals to 11 .so we find out 5 and 6
