Hello,
[tex]z=\dfrac{X-69}{3.5} \\\\For\ X=72.5, \\\\z=\dfrac{72.5-69}{3.5} =1\\[/tex]
Using table of a normal reduced law:
p(z≤1)=0.8413
Thus p(z≥1)=1-0.8413=0.1587
There are 80*0.1587=12.696 ≈13 (frogs)
Answer:
12 frogs
Step-by-step explanation:
Hello,
Using table of a normal reduced law:
p(z≤1)=0.8413
Thus p(z≥1)=1-0.8413=0.1587
There are 80*0.1587=12.696 ≈12 (frogs) you don't round up because you cant have .7 percent of a frog.
ps. I copy and pasted caylus's response but corrected their answer because it was correct except the rounding up part.
