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A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the final volume is 13.8 L? Please show your work in order to receive credit.

Respuesta :

Answer:

474. 64 mm Hg

Explanation:

  • P1 = 655 mm Hg
  • V1 = 10 L

  • P2 = ?
  • V2 = 13. 8 L

using Boyle's Law that is

P1. V1 = P2. V2

655 × 10 = P2 × 13. 8

[tex]P2 = \frac{655 \times 10}{13.8} [/tex]

P2 = 474. 64 mm Hg

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