A4.60pf capacitor that is initially uncharged is connected in series with a 7.50kohms resistor and an emf source with E=125V and negligible internal resistance. Just after the circuit is completed, what are; a. The voltage drop across the capacitor b. The voltage drop across the resistor c. The charge on the capacitor d. The current through the resistor e.

Respuesta :

Answer:

a)   [tex]V_c=0[/tex]

b)  [tex]V_R=145V[/tex]

c)  [tex]Q_c=0[/tex]

d) [tex]I=\frac{1}{60}A[/tex]

Explanation:

From the question we are told that:

Capacitor [tex]C=4.60[/tex]

Resistor [tex]R=7.50[/tex]

Source emf [tex]E=125V[/tex]

a)

Generally The voltage drop across the capacitor is

V_c=0

b)

Generally the equation for Voltage drop is mathematically given by

[tex]V=IR[/tex]

[tex]V=\frac{E}{R}*R[/tex]

[tex]V_R=145V[/tex]

c

Generally The Charge across the capacitor is

[tex]Q_c=0[/tex]

d)

Generally the equation for Current is mathematically given by

[tex]I=\frac{V}{R}[/tex]

[tex]I=\frac{125}{7.5*10^3}[/tex]

[tex]I=\frac{1}{60}A[/tex]