Answer:
The quadrilateral is a rhombus
Step-by-step explanation:
Given
[tex]A = (2, 8)[/tex]
[tex]B = (3, 11)[/tex]
[tex]C = (4, 8)[/tex]
[tex]D=(3, 5)[/tex]
Required
The true statement
Calculate slope (m) using
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Calculate distance using:
[tex]d= \sqrt{(x_2 - x_1)^2 + (y_2 -y_1)^2}[/tex]
Calculate slope and distance AB
[tex]m_{AB} = \frac{11 - 8}{3 - 2}[/tex]
[tex]m_{AB} = \frac{3}{1}[/tex]
[tex]m_{AB} = 3[/tex] -- slope
[tex]d_{AB}= \sqrt{(3 - 2)^2 + (11 -8)^2}[/tex]
[tex]d_{AB}= \sqrt{10}[/tex] -- distance
Calculate slope and distance BC
[tex]m_{BC} = \frac{8 - 11}{4 - 3}[/tex]
[tex]m_{BC} = \frac{- 3}{1}[/tex]
[tex]m_{BC} = -3[/tex] -- slope
[tex]d_{BC} = \sqrt{(4-3)^2+(8-11)^2[/tex]
[tex]d_{BC} = \sqrt{10}[/tex] --- distance
Calculate slope CD
[tex]m_{CD} = \frac{5 - 8}{3 - 4}[/tex]
[tex]m_{CD} = \frac{- 3}{- 1}[/tex]
[tex]m_{CD} = 3[/tex] -- slope
[tex]d_{CD} = \sqrt{(3-4)^2+(5-8)^2}[/tex]
[tex]d_{CD} = \sqrt{10}[/tex] -- distance
Calculate slope DA
[tex]m_{DA} = \frac{8 - 5}{2 - 3}[/tex]
[tex]m_{DA} = \frac{3}{- 1}[/tex]
[tex]m_{DA} = -3[/tex] -- slope
[tex]d_{DA} = \sqrt{(2-3)^2 + (8-5)^2}[/tex]
[tex]d_{DA} = \sqrt{10}[/tex]
From the computations above, we can see that all 4 sides are equal, i.e. [tex]\sqrt{10}[/tex]
And the slope of adjacent sides are negative reciprocal, i.e.
[tex]m_{AB} = 3[/tex] and [tex]m_{CD} = -3[/tex]
[tex]m_{CD} = 3[/tex] and [tex]m_{DA} = -3[/tex]
The quadrilateral is a rhombus
