A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no precipitate forms. An excess of lithium sulfate is then added to the solution and a precipitate forms. The precipitate is filtered off and lithium phosphate is added to the remaining solution, producing a precipitate. Which ions are present in the original solution

Question

contestada

Respuesta :

aristeus aristeus · Answer 1 · 2021-07-13T14:08:54+02:00

Answer:

[tex]Ca^{2+} and Co^{2+}[/tex]

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, [tex]Ca_2[/tex] and [tex]Co_2[/tex]

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding [tex]Li_2SO_4[/tex] to it precipitation takes place.

Precipitate is as follows,

[tex]Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)[/tex]

Thus,

[tex]Ca^2^+[/tex] is present

When [tex]Li_3PO_4[/tex] is added again precipitation takes place.

Therefore the reaction is as follows,

[tex]Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)[/tex]

Therefore,

[tex]Ca^{2+} and Co^{2+}[/tex] are present in the solution