Answer:
Solution given:
Centre (h,k)=(-6,-2)
end points are:
A[tex]\bold{(x_{1},y_{1})=(-1,-9) \:and \:B(x_{2},y_{2})=(-11,5)}[/tex]
Now
distance between A to M is:
AM=[tex]\sqrt{(h-x_{1})²+(k-y_{1})²}[/tex]
AM=[tex]\sqrt{(-6+1)²+(-2+9)²}=8.6[/tex]units
again
distance between B to M is:
BM=[tex]\sqrt{(h-x_{2})²+(k-y_{2})²}[/tex]
BM=[tex]\sqrt{(-6+11)²+(-2-5)²}=8.6[/tex]units
again
Since AM=BM=8.6units
so
M is the centre of the circle.:Yes
