Use special right triangle ratios to find the lengths of the other leg and the hypotenuse

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JackTheTaco JackTheTaco

09-07-2021
Mathematics

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Use special right triangle ratios to find the lengths of the other leg and the hypotenuse

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wegnerkolmp2741o wegnerkolmp2741o · Answer 1 · 2021-07-09T17:16:19+02:00

wegnerkolmp2741o wegnerkolmp2741o

09-07-2021

Answer:

leg = 18

hypotenuse = 18 sqrt(2)

Step-by-step explanation:

We know that sin theta = opp side / hypotenuse

sin 45 = 18 / hyp

hyp sin 45 = 18

hyp = 18 / sin 45

hyp = 18 sqrt(2)

Since this is an isosceles triangle ( the two angles are the same measure), the two legs have to be the same length

leg = 18

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msm555 msm555 · Answer 2 · 2021-07-09T17:24:51+02:00

msm555 msm555

09-07-2021

the lengths of the other leg and the hypotenuse

is 18 units and 18[tex]\sqrt{2}[/tex]units respectively.

Answer:

Solution given:

Let <C=<B=45°

AB=18 units

BC=?

AC=?

again

By using

By usingspecial right triangle ratios

sin C=opposite/hypotenuse=AB/AC=18/AC

Sin 45=18/AC

AC=18/sin45

AC=hypotenuse=18[tex]\sqrt{2}[/tex]units

again

Tan A=opposite/adjacent=BC/AB=BC/18

Tan45=BC/18

BC=Tan45*18

BC=length of another leg=18 units.

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