Answer:
[tex]9x+4x^2-5y[/tex]
Step-by-step explanation:
Hi there!
Length of the field: [tex]14x-3x^2+2y[/tex] units
Width of the field: [tex]5x-7x^2+7y[/tex] units
To find how much greater the length of the field is than the width, subtract the width from the length:
[tex]14x-3x^2+2y-(5x-7x^2+7y)[/tex]
Open up the parentheses
[tex]= 14x-3x^2+2y-5x+7x^2-7y[/tex]
Combine like terms
[tex]= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y[/tex]
Therefore, the length is [tex]9x+4x^2-5y[/tex] units greater than the width.
I hope this helps!
