Answer:
[tex]P(TTTTT) = \frac{1}{32}[/tex]
Step-by-step explanation:
Given
[tex]n = 5[/tex] --- toss
See comment for complete question
Required
[tex]P(TTTTT)[/tex]
First, we calculate the number of possible outcomes
A coin has 2 faces; Since the coin is to be tossed 5 times;
[tex]Outcome = 2^5[/tex]
[tex]Outcome = 32[/tex]
There is only one outcome of TTTTT;
So:
[tex]P(TTTTT) = \frac{1}{32}[/tex]