Respuesta :

msm555

Answer:

Solution given:

f(x)=5x-3

let

y=f(x)

y=5x-3

interchanging role of x and y

x=5y-3

x+3=5y

y=[tex]\frac{x+3}{5}[/tex]

$o,

f-¹(x)=[tex]\frac{x+3}{5}[/tex]

we conclude that

f-¹(x)≠g(x)

Each pair of function are not inverses.

g(x)=x/5+3

let g(x)=y

y=x/5+3

interchanging role of x and y

x=y/5+3

x-3=y/5

doing crisscrossed multiplication

5(x-3)=y

y=5x-15

g-¹(x)=5x-15

So

g-¹(x)≠f-¹(x)

Each pair of function are not inverses.

ItzTds

Given that,

→ f(x) = 5x-3

Then y = f(x),

→ y = 5x-3

Now we can interchange role of x and y,

→ x = 5y-3

Then use the cross multiplication,

→ x+3 = 5y

→ y = x+3/5

Now the inverse is,

→ f-¹(x) = x+3/5

We can go to the conclusion that,

→ f-¹(x) ≠ g(x)

So, each pair of function is not inverse.

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