Answer:
[tex]-\frac{5}{2} x^{3} +\frac{17}{8} x^{2} -15[/tex]
Step-by-step explanation:
First combine like terms so for numbers with x^3 you have one:
-[tex]\frac{5}{2} x^{3}[/tex]
Then x^ 2
[tex]\frac{9}{8}x^{2} +x^{2}[/tex]
(4/4x^2 is just x^2 because 4/4 is 1)
So
[tex]\frac{17}{8} x^{2}[/tex]
Then all numbers with x cancel out because
2x+3x-5x is 0.
Then you just have -15.
So put them back together to get what I wrote in the answer.
Hope that helps lmk if I calculated that wrong!
