Answer:
4.15×10²² atoms of C are contained in 1 g of butane.
Explanation:
Formula for butane is C₄H₁₀
1 mol of butane contains 4 moles of carbon and 10 moles of H
Molecular weight is 58 g/mol
In conclussion we can say that 58 g of butane contain 4 moles of C and 10 moles of H
We prepare the rule of three:
1 g . 4 moles of C / 58g = 0.0689 moles of C
Now we can count the atoms by NA. We know that 6.02×10²³ particles are contained in 1 mol of anything.
0.0689 mol . 6.02×10²³ atoms / 1mol = 4.15×10²²
4.15×10²² atoms of C are contained in 1 g of butane.
