Respuesta :

Answer:

OA⊥OC

∴∠AOB+BOC= 90°

5x+8+6n-6=90

11x+2=90

x=90-2/11

x=88/11

x=8

∠BOC=6x-6

=6(8)-6

=48-6

∠BOC=42°

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Hope it helps...

Have a great day!!

Answer:

[tex]<BOC = 42[/tex]

Step-by-step explanation:

In this problem, it is given that lines (AO) and (OC) are perpendicular. This means that when the lines intersect, the four angles formed each have a measure of (90) degrees. As per the given diagram, angles (<AOR) and (<ROC) add up to make (<AOC). Thus, one can form the following equation and solve for (x).

[tex](<AOR) + (<ROC) = (<AOC)[/tex]

Substitute,

[tex](6x-6)+(5x+8)=90[/tex]

Simplify,

[tex]11x+2=90[/tex]

Inverse operations,

[tex]11x+2=90[/tex]

[tex]11x=88\\\\x=8[/tex]

Substitute this into the equation for the measure of angle (<BOC) to find the numerical angle measure:

[tex]<BOC = 6x-6\\x = 8\\\\= 6(8)-6\\\\=48-6\\\\=42[/tex]