need help with this problem

Answer:
OA⊥OC
∴∠AOB+BOC= 90°
5x+8+6n-6=90
11x+2=90
x=90-2/11
x=88/11
x=8
∠BOC=6x-6
=6(8)-6
=48-6
∠BOC=42°
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Hope it helps...
Have a great day!!
Answer:
[tex]<BOC = 42[/tex]
Step-by-step explanation:
In this problem, it is given that lines (AO) and (OC) are perpendicular. This means that when the lines intersect, the four angles formed each have a measure of (90) degrees. As per the given diagram, angles (<AOR) and (<ROC) add up to make (<AOC). Thus, one can form the following equation and solve for (x).
[tex](<AOR) + (<ROC) = (<AOC)[/tex]
Substitute,
[tex](6x-6)+(5x+8)=90[/tex]
Simplify,
[tex]11x+2=90[/tex]
Inverse operations,
[tex]11x+2=90[/tex]
[tex]11x=88\\\\x=8[/tex]
Substitute this into the equation for the measure of angle (<BOC) to find the numerical angle measure:
[tex]<BOC = 6x-6\\x = 8\\\\= 6(8)-6\\\\=48-6\\\\=42[/tex]