d) A product contains three lasers, and the product fails if any of the lasers fails. Assume the lasers fail independently. What should the mean life equal for 99% of the products to exceed 10000 hours before failure

Respuesta :

Solution :

Let the probability laser works = p

The probability that the system works = [tex]$P(\text{all three component works}) = p^3 $[/tex]

                                                                                                                   = 0.99

Therefore, p = 0.9967

Now for the above probability critical z = -2.72

Hence, the mean life is equal to = [tex]10,000 + 2.72 \times 600[/tex]

                                                     = [tex]10,000+1632[/tex]

                                                     [tex]=11,632[/tex]