Answer:
The y-coordinate of point A is [tex]\sqrt{3}[/tex].
Step-by-step explanation:
The equation of the circle is represented by the following expression:
[tex](x-h)^{2}+(y-k)^{2} = r^{2}[/tex] (1)
Where:
[tex]x[/tex] - Independent variable.
[tex]y[/tex] - Dependent variable.
[tex]h[/tex], [tex]k[/tex] - Coordinates of the center of the circle.
[tex]r[/tex] - Radius of the circle.
If we know that [tex]h = 0[/tex], [tex]k = 0[/tex] and [tex]r = 2[/tex], then the equation of the circle is:
[tex]x^{2} + y^{2} = 4[/tex] (1b)
Then, we clear [tex]y[/tex] within (1b):
[tex]y^{2} = 4 - x^{2}[/tex]
[tex]y = \pm \sqrt{4-x^{2}}[/tex] (2)
If we know that [tex]x = 1[/tex], then the y-coordinate of point A is:
[tex]y = \sqrt{4-1^{2}}[/tex]
[tex]y = \sqrt{3}[/tex]
The y-coordinate of point A is [tex]\sqrt{3}[/tex].
