Respuesta :
Answer:
The number of newborns who weighed between 1614 grams and 5182 grams was of 586.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The mean weight was 3398 grams with a standard deviation of 892 grams.
This means that [tex]\mu = 3398, \sigma = 892[/tex]
Proportion that weighed between 1614 and 5182 grams:
p-value of Z when X = 5182 subtracted by the p-value of Z when X = 1614.
X = 5182
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{5182 - 3398}{892}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a p-value of 0.9772
X = 1614
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1614 - 3398}{892}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a p-value of 0.0228
0.9772 - 0.0228 = 0.9544.
Out of 614 babies:
0.9544*614 = 586
The number of newborns who weighed between 1614 grams and 5182 grams was of 586.
