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SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is interested in estimating the average SAT score of first-year students. If the administrator would like to limit the margin of error of the 82% confidence interval to 25 points, how many students should the administrator sample

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Cricetus

Answer:

The appropriate solution is "259".

Step-by-step explanation:

According to the question,

[tex]\sigma = 300[/tex]

[tex]M.E=25[/tex]

At 82% CI,

[tex]\alpha = 0.18[/tex]

Critical value,

[tex]Z_c=1.341[/tex]

Now,

The sample size will be:

⇒ [tex]n=(Z_c\times \frac{\sigma}{E} )^2[/tex]

By substituting the values, we get

      [tex]=(1.341\times \frac{300}{25} )^2[/tex]

      [tex]=(1.341\times 12)^2[/tex]

      [tex]=259[/tex]