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Suppose a 42-turn coil lies in the plane of the page in a uniform magnetic field that is directed into the page. The coil originally has an area of 0.125 m2. It is stretched to have no area in 0.100 s. What is the magnitude (in V) and direction (as seen from above) of the average induced emf if the uniform magnetic field has a strength of 1.40 T

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Answer:

EMF =  73.5 volts

Explanation:

Given that,

The number of a coil, N = 42

The area of the coil, A = 0.125 m²

It is stretched to have no area in 0.100 s

The magnetic field strength is 1.4 T.

We need to find the average induced emf in the coil. We know that,

[tex]\epsilon=N\dfrac{d\phi}{dt}[/tex]

[tex]\epsilon=N\dfrac{BA}{dt}\\\\\epsilon=42\times \dfrac{1.4\times 0.125}{0.1}\\\\=73.5\ V[/tex]

So, the induced emf in the coil is 73.5 volts.

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