Answer:
The molality of solution=12.605 m
Explanation:
We are given that
Molar mass of Hydrogen peroxide, M=34 g/mol
Density of solution, [tex]\rho=1.11gcm^{-3}[/tex]
30% Means mass of solute (Hydrogen peroxide)=30 g
Mass of solvent =100-30=70 g
Total mass of solution, m=100 g
Number of moles of solute=[tex]\frac{given\;mass}{molar\;mass}[/tex]
Using the formula
Number of moles of hydrogen peroxide=[tex]\frac{30}{34}[/tex]
Now, molality of solution
[tex]m=\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}\times 1000[/tex]
[tex]m=\frac{30}{70\times 34}\times 1000[/tex]
[tex]m=12.605 m[/tex]
Hence, the molality of solution=12.605 m