algebra 2 test prep pls help

Answer:
[tex]\frac{\sqrt{117} }{11}[/tex]
Step-by-step explanation:
sin²β + cos²β = 1
sin²β = 1 - ( - [tex]\frac{2}{11}[/tex] )²
sin²β = 1 - [tex]\frac{4}{121}[/tex] = [tex]\frac{117}{121}[/tex]
sin β > 0 ( Q. ll )
sin β = [tex]\frac{\sqrt{117} }{11}[/tex]
sin[tex]\theta_{1}=\frac{\sqrt{117}}{11}[/tex]
Answer:
Solution given:
[tex]\bold{Cos \theta_{1}=\frac{-2}{11}}[/tex]
squaring both side we get
[tex]\bold{Cos² \theta_{1}=\frac{4}{121}}[/tex]
1-sin²[tex]\theta_{1}=\frac{4}{121}[/tex]
sin²[tex]\theta_{1}=1-\frac{4}{121}[/tex]
sin[tex]\theta_{1}=\sqrt{\frac{117}{121}}[/tex]
sin[tex]\theta_{1}=\frac{\sqrt{117}}{11}[/tex]