Complete Question
Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail
Answer:
[tex]F=2*10^{4}N[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=0.500kg[/tex]
Initial Velocity [tex]V=15.0m/s[/tex]
Distance [tex]x=2.80mm=>0.00280m[/tex]
Diameter [tex]d=2.50mm=>0.00250m[/tex]
Length [tex]l=6.00cm=>0.6m[/tex]
Generally the equation for Force is mathematically given by
[tex]F=\frac{mv^2}{2d}[/tex]
[tex]F=\frac{0.500*15^2}{2.80*10^{-3}}[/tex]
[tex]F=2*10^{4}N[/tex]
