Answer:
y+6=1/2(x+3)
Step-by-step explanation:
Hi there!
We want to find the equation of the line in point-slope form that passes through (-3, -6), and (3, -3)
Point-slope form is given as y-[tex]y_{1}[/tex]=m(x-[tex]x_{1}[/tex]) where ([tex]x_{1}[/tex], [tex]y_{1}[/tex]) is a point and m is the slope
We don't know the slope of the line, so let's find it
The formula for the slope (m) calculated from two points is [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex], where ([tex]x_{1}[/tex], [tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points
We have two points, but let's label their values to avoid any confusion
[tex]x_{1}[/tex]=-3
[tex]y_{1}[/tex]=-6
[tex]x_{2}[/tex]=3
[tex]y_{2}[/tex]=-3
Now substitute into the formula (remember: the formula has SUBTRACTION)
m=[tex]\frac{-3--6}{3--3}[/tex]
simplify
m=[tex]\frac{-3+6}{3+3}[/tex]
m=[tex]\frac{3}{6}[/tex]
m=1/2
So the slope of the line is 1/2
Now that we have everything needed for point-slope form (a point and the slope), substitute the values into the formula (remember: the formula has SUBTRACTION)
y-[tex]y_{1}[/tex]=m(x-[tex]x_{1}[/tex])
y--6=1/2(x--3)
simplify
y+6=1/2(x+3)
Hope this helps!
