Answer:- 10[tex]m^{2}[/tex] + 3m -9
Step-by-step explanation: Given ;
A= -3 -m
B= 3m -5[tex]m^{2}[/tex]
2B + 3A
solution
2B + 3A
substitute A and B in the formula
2(3m - 5[tex]m^{2}[/tex]) + 3(-3 -m)
6m - 10[tex]m^{2}[/tex] - 9 - 3m group like terms
- 10[tex]m^{2}[/tex] + (6m -3m) -9
- 10[tex]m^{2}[/tex] + 3m -9
