Answer:
[tex]y=\displaystyle \frac{1}{2}x+1[/tex]
Step-by-step explanation:
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept.
We're given the x-intercept, -2, and the y-intercept, 1. We can directly plug the y-intercept into the equation [tex]y=mx+b[/tex] :
[tex]y=mx+1[/tex]
Now, we must solve for the slope. The x-intercept -2 gives us the point (-2,0), since the x-intercept occurs when y=0. Plug this point into the equation and solve for m:
[tex]0=m(-2)+1\\0=-2m+1\\-1=-2m\\\\\displaystyle m=\frac{-1}{-2} \\\\\displaystyle m=\frac{1}{2}[/tex]
Therefore, the slope of the line is [tex]\displaystyle \frac{1}{2}[/tex]. Plug this back into [tex]y=mx+1[/tex]:
[tex]y=\displaystyle \frac{1}{2}x+1[/tex]
I hope this helps!
