The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
What is the quadratic formula?
A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
How to solve the question?
In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
To find the quadratic equation for which we use the quadratic formula
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
we compare this equation with the standard quadratic formula,
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.
Now, we convert the given options in the standard form to check for the correct choice:
- A. x² + 1 = 2x - 3 ⇒ x² - 2x + 4 = 0, which is not the correct choice.
- B . x² - 2x - 1 = 3 ⇒ x² - 2x - 4 = 0, which is not the correct choice.
- C. x² + 2x - 1 = 3 ⇒ x² + 2x - 4 = 0, which is the correct choice.
- D. x² + 2x - 1 = -3 ⇒ x² + 2x + 2 = 0, which is not the correct choice.
Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
Learn more about the quadratic formula at
https://brainly.com/question/1214333
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