Answer:
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Step-by-step explanation:
Say the height of the room is X metres. So the length is 3X, and the breadth is length/2, or 3X/2.
The area of the 4 walls is then 3x^2 + 3X^2 + 3X^2/2 +3X^2/2 = 9X^2
If the cost of plastering is R5/sq m, then 9X^2 * 5 = 720
Solving this gives X = 4 m - a rather high ceiling
The floor area is then (3*4) * (3*4/2) = 72 sq m
Carpeting is then 250*72 = R18000
