PLEASE HELP!!
Find the area of the sector.

Answer:
B.
[tex] \frac{275\pi}{6} {m}^{2} [/tex]
Step-by-step explanation:
[tex]area \: of \: sector \: is \\ \frac{the \: angle}{360} \times \pi {r}^{2} \\ hence \: we \: have \\ \frac{165}{360} \times {(10m)}^{2} = \frac{275\pi}{6} {m}^{2} [/tex]