m/HCB = 60°, m/DCB = 9x-1, and m/DCH = 2x+ 16. Find x

Answer:
[tex]x=11[/tex]
Step-by-step explanation:
Note that ∠DCB is the sum of ∠HCB and ∠DCH. Hence:
[tex]m\angle DCB = m\angle HCB + m\angle DCH[/tex]
Substitute in the appropriate values/expressions:
[tex](9x-1) = (60) + (2x+16)[/tex]
Solve for x. Combine like terms:
[tex]9x - 1 = 2x + 76[/tex]
Subtract 2x from both sides:
[tex]7x - 1 = 76[/tex]
Add one to both sides:
[tex]7x = 77[/tex]
And divide. Hence:
[tex]x=11[/tex]
Answer:
x=11
Step-by-step explanation:
<DCB = <DCH + < HCB
9x-1 = 2x+16 + 60
Combine like terms
9x-1 = 2x+76
Subtract 2x from each side
9x-1-2x= 2x+76-2x
7x-1 = 76
Add 1 to each side
7x-1 +1 = 76+1
7x = 77
Divide by 7
7x/7 = 77/7
x=11