Respuesta :

Bora77

Answer:

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[tex]4 {x}^{2} - 25 {y}^{2} \\ (2 x) {}^{2} - {(5y)}^{2} \\ (2x + 5y)(2x - 5y)[/tex]

Tasyha

Answer:

[tex] = 1)(2x - 5y {)} \times (2x + 5y)[/tex]

Step-by-step explanation:

[tex]1) {4x}^{2} - 25 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - 25 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - {5}^{2} {y}^{2} [/tex]

[tex] = (2 {x)}^{2} - {5}^{2} {y}^{2} [/tex]

[tex] = ( {2x)}^{2} - (5 {y)}^{2} [/tex]

[tex] = (2x - 5y) \times (2x + 5y)[/tex]

[tex]2)4x^{2} - 35 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - 5y \times 7 {y} [/tex]

[tex] =(2x {)}^{2} - (5y \times 7y)[/tex]