Respuesta :
Answer:
[tex](x,y) = ( 5 , - 7)[/tex]
Step-by-step explanation:
we would like to solve the following system of linear equation by substitution:
[tex] \displaystyle \begin{cases} y = x - 12\\ 8x + 8y = - 16\end{cases}[/tex]
notice that, we're already given the value of y therefore simply substitute it to the II equation
[tex]8x + 8(x - 12) = - 16[/tex]
distribute:
[tex]8x + 8x - 96= - 16[/tex]
simplify addition:
[tex]16 x- 96= - 16[/tex]
isolate -96 to left hand side and change its sign:
[tex]16 x= - 16 + 96[/tex]
simplify addition:
[tex]16 x= 80[/tex]
divide both sides by 16 and that yields:
[tex] \boxed{x= 5}[/tex]
now substitute the got value of x to the first equation:
[tex]y = 5- 12[/tex]
simplify subtraction:
[tex]y = - 7[/tex]
hence,
the solution is (x,y)=(5,-7)
G I V E N :
Solve by substitution :
y = x - 12
8x + 8y = -16
S O L U T I O N :
y = x - 12 ------- eq(1)
8x + 8y = -16 ------- eq(2)
Finding x ⤵
Putting y = x - 12 in eq(2) we get
- 8x + 8(x - 12) = -16
- 8x + 8x - 96 = -16
- 16x = 96 - 16
- 16x = 80
- x = 80/16
- x = 5
Finding y ⤵
Putting x = 5 in eq(1) we get
- y = x - 12
- y = 5 - 12
- y = -7
Hence, x is 5 and y is -7