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2. A 15.0 N force is used to hold a mass on a string at an angle of 32° from the vertical, as in the
below diagram.
32
F = 15.0 N
What is the mass? (ans: 2.9 kg)
As u can see I have the answer so plz just show ALL STEPS

2 A 150 N force is used to hold a mass on a string at an angle of 32 from the vertical as in the below diagram 32 F 150 N What is the mass ans 29 kg As u can se class=

Respuesta :

rMelon

Answer: 2.9kg

let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.

represent the mass. By resolving forces, we have:

F=mgSin(theta)

15N=mgSin(32°)

m=15N/g×Sin(32°)

m=15N/9.8m/s^2÷Sin(32°)

=2.888kg2.888

≈2.9kg

Mass on a string will be 2.9 kg

What is equilibrium condition?

Object at equilibrium is the condition in which all the forces are balanced and the object will not accelerate and net force on the object will be zero

given

mass = ?

Force = F = 15N

angle from the vertical = 32°

according to newton' s law of equation, because of equilibrium condition

mg sin(32°) - F =0

m(9.8) (0.5299) - 15 =0

5.19302 m = 15

m= 15/5.19302 = 2.8885 = 2.9 kg

Mass on a string will be 2.9 kg

learn more about equilibrium

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