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Suppose h” is continuous at x = 2,h' (2) = 0, and h” (2) < 0.
What can you say about the behavior of h at X = 2?

Respuesta :

caylus

Answer:

Hello,

Step-by-step explanation:

h(x) has a minimum at x=  2. (h(x) is turning down at x=2)

I have suppose that h''(2 + ) <0 and h''(2 -) <0

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