ABCD is a quadrilateral, P Q R and S divide AB, CB, CD and AD in ratio 1:3 respectively. Prove that a//m. (Please hurry up, I will mark you as Brainliest) ​

Respuesta :

Two lines are parallel if they are equidistant from one another. The following proves [tex]a || m[/tex]

[tex]Ratio = 1:3[/tex] means that:

[tex]BP=3PA[/tex]

[tex]BQ=3QC[/tex]

To prove that [tex]a || m[/tex] is to prove that side length SR and side length PQ are parallel because:

[tex]SR = a\\ PQ = m[/tex] --------- See attachment for quadrilateral

Considering [tex]\triangle ABC[/tex], we have: [tex]BP=3PA[/tex]

Divide both sides by PA

[tex]\frac{BP}{PA} = \frac{3PA}{PA}[/tex]

[tex]\frac{BP}{PA} = 3[/tex]

Similarly: [tex]BQ=3QC[/tex]

Divide both sides by QC

[tex]\frac{BQ}{QC} = \frac{3BQ}{QC}[/tex]

[tex]\frac{BQ}{QC} = 3[/tex]

So, we have:

[tex]\frac{BP}{PA} = \frac{BQ}{QC} = 3[/tex]

Express as ratios

[tex]BP:PA = BQ:QC = 3[/tex]

[tex]BP:PA \to[/tex] means point P divided side length BA into 3:1

[tex]BQ:QC \to[/tex] means point Q divided side length BC into 3:1

Thales Theorem states that: A line that divides any two sides of a triangle in the same ratio is parallel to the third side.

The third side of [tex]\triangle ABC[/tex] is [tex]AC[/tex].

This means that: [tex]PQ[/tex] is parallel to [tex]AC[/tex]

Since [tex]AC[/tex] is parallel to [tex]SR[/tex], then [tex]PQ[/tex] is parallel to [tex]SR[/tex]

i.e. [tex]SR || PQ[/tex]

Recall that:

[tex]SR = a\\ PQ = m[/tex]

Hence:

[tex]a || m[/tex] has been proved.

Read more about proof of parallel sides at:

https://brainly.com/question/2510808

Ver imagen MrRoyal