Help with this? Anyone know how to do it? It’s due in the morning

Using pythagorean theorem
[tex]\\ \sf\longmapsto B^2=H^2-P^2[/tex]
[tex]\\ \sf\longmapsto x^2=13^2-5^2[/tex]
[tex]\\ \sf\longmapsto x^2=169-25[/tex]
[tex]\\ \sf\longmapsto x^2=144[/tex]
[tex]\\ \sf\longmapsto x=\sqrt{144}[/tex]
[tex]\\ \sf\longmapsto x=12[/tex]
Answer:
x = 12
Step-by-step explanation:
→ State Pythagoras theorem
a² + b² = c²
→ Rearrange to make b the subject
b² = c² - a²
→ Square root everything
b = √c² - a²
→ Substitute in the numbers
b = √13² - 5²
→ Simplify
b = 12