Respuesta :

LammettHash

The student's measurement was off by an absolute error of

|2.9 cm - 2.6 cm| = 0.3 cm

The percent error in the measurement is the absolute error divided by the actual length of the string,

(0.3 cm) / (2.9 cm) ≈ 0.103 = 10.3%

Otras preguntas