Find the value of x in the triangle shown below.(not a test just need help with khan academy)

Using angle sum property
[tex]\\ \sf\longmapsto x+44+29=180[/tex]
[tex]\\ \sf\longmapsto x+63=180[/tex]
[tex]\\ \sf\longmapsto x=180-63[/tex]
[tex]\\ \sf\longmapsto x=117°[/tex]
The angle sum property of a triangle:
[tex]\large\bf{\red{ \longrightarrow}} \: \tt \: x \: + \: 44 \degree \: + \: 29 \degree \: = \: 180 \degree[/tex]
[tex]\large\bf{\red{ \longrightarrow}} \: \tt \: x \: + \: 73 \degree \: = \: 180 \degree[/tex]
[tex]\large\bf{\red{ \longrightarrow}} \: \tt \: x \: = \: 180 \degree \: - \: 73 \degree \:[/tex]
[tex]\large\bf{\red{ \longrightarrow}} \: \tt \: x \: = \: 107 \degree[/tex]