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To draw a graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of ___, a second point by going over 3 and up ___, and then draw a line through the points

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I got b5
At least that’s what I got

For drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

How to know if a point lies in the graph of a function?

All the points (and only those points) which lie on the graph of the function satisfy its equation.

Thus, if a point lies on the graph of a function, then it must also satisfy the function.

For this case, the equation given to us is:

[tex]y = \dfrac{3}{4}x + 7[/tex]

Any equation of the form [tex]y = mx + c[/tex] where m and c are constants and x and y are variables is the equation of a straight line.

For a straight line to be characterized, only two points are sufficient.

For x = 0, the y-coordinate would be such that it would satisfy the equation [tex]y = \dfrac{3}{4}x + 7[/tex]

Putting x = 0, we get:

[tex]y = \dfrac{3}{4} \times 0 + 7 = 7[/tex]

Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 7. Thus, (0,7) is one of the point's coordinate on the considered line.

Putting x = 3, we get:

[tex]y = \dfrac{3}{4} \times 3 + 7 = 9.25[/tex]

Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 9.25 . Thus, (0,9.25) is another of the point's coordinate on the considered line.

Thus, for drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

Learn more about points lying on graph of a function here:

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