Answer:
[tex](x-5)^2+(y+3)^2=10[/tex]
Step-by-step explanation:
equation of a circle: (x – h)^2 + (y – k)^2 = r^2 where (h,k) is the center
The center of the circle is at (5, -3)
(x-5)^2+(y+3)^2
To find the radius, use distance formula: [tex]\sqrt{(x_{1}-x_{2})^2 + (y_{1}-y_{2})^2}[/tex]
[tex]\sqrt{(6-5)^2 + (3)^2}[/tex]
[tex]\sqrt{1^2 + 3^2} = \sqrt{1+9} = \sqrt{10}[/tex]
[tex](x-5)^2+(y+3)^2=10[/tex]
