The average bond order is the number of bonds between two atoms taking into account resonance.
a. Draw a Lewis structure for the nitrite ion and answer the questions below.
1. there are equivalent Lewis structures for NO2-.
2. the average N-O bond order is .
b. Draw a Lewis structure for sulfur dioxide and answer the questions below.
1. there are equivalent Lewis structures for SO2.
2. the average S-O bond order is _______.

Question

10-08-2021
Chemistry

contestada

The average bond order is the number of bonds between two atoms taking into account resonance.
a. Draw a Lewis structure for the nitrite ion and answer the questions below.
1. there are equivalent Lewis structures for NO2-.
2. the average N-O bond order is .
b. Draw a Lewis structure for sulfur dioxide and answer the questions below.
1. there are equivalent Lewis structures for SO2.
2. the average S-O bond order is _______.

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ItzImran01 ItzImran01 · Answer 1 · 2021-08-10T07:27:48+02:00

1. Sulfur dioxide, or SO2 , has two resonance structures which contribute equally to the overall hybrid structure of the molecule. However, a third Lewis structure can be drawn for SO2 which is more stable in theory, but doesn't quite match experimental data.

2.

[tex] \color{red} = \frac{No. \: of \: bonding \: electron \: pairs}{No. \: of \: bonded \: atoms} [/tex]

[tex]In \: each \: resonance \: contributor, \\ there \: are \: six \: bonding \: electron \\ pairs \: and \: four \: atoms \: bonded \\ to \: the \: SS \: atom. \: Thus,[/tex]

[tex]BO = \frac{6}{4} = 1.5

[/tex]