35) Like J is represented by the equation 3x-2y=10. Line M is perpendicular to line J at (6,-1) What is the equation of Line M

Answer:
y=-2/3x+3
Step-by-step explanation:
the equation of line J is y=3/2x-5
perpendicular slope would be -2/3
you want it at point (6, -1) so sub the points into y=-2/3x+b
-1=-2/3(6)+b
-1=-4+b
3=b
y=-2/3x+3