5(^ 1/5 +-4) 2(-4)(-0.8)^ 2

Answer:
Step-by-step explanation:
[tex]\displaystyle\ \Large \boldsymbol{} \frac{5(\frac{1}{5}+(-4) )}{2\cdot(-4) \cdot (0-0,8)^2} =\frac{^1 \ 5^{ }\!\!\!\!\diagup\cdot \frac{1}{5\!\!\!\!\diagup}-20 }{-8 \cdot 0,64 } = \\\\\\ \frac{-20+1}{-5,12} =\frac{-19}{-5,12} \cdot \frac{25}{25} =\frac{475}{128} =\boxed{\pmb{3\frac{91}{128} }}[/tex]