Respuesta :

r3t40

Start with a volume of a cuboid,

[tex]V=abc=3\cdot2\cdot3=18\mathrm{cm^3}[/tex]

The side of the cube we need equals to the LCM of the cubiod's sides,

[tex]\mathrm{LCM}(a,b,c)=\mathrm{LCM}(3,2,3)=6[/tex]

Now compute the volume of such cube,

[tex]V=\mathrm{LCM}(a,b,c)^3=6^3=216\mathrm{cm^3}[/tex]

Divide the volumes to get how many cubiods are in such cube,

[tex]\dfrac{V_{\mathrm{cube}}}{V_{\mathrm{cubiod}}}=\dfrac{216}{18}=\boxed{12}[/tex]

Hope this helps :)

caylus

Answer:

Hi,

Answer: 12

Step-by-step explanation:

lcm(3,2,3)=6

Volume of a cuboid=3*2*3=18 (cm³)

Volume of the cube=6³=216 (cm³)

Number of cuboids=216/18=12.

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