f is a function defined by
{(-3, 1), (-2, 2), (-1, -3), (0, -1), (1, 3), (2, -2), (3, 0)}
so f (1) = 3. Then
h (g (i (j (f (1))))) = h (g (i (j (3))))
j is defined by
{(-3, 0), (-2, 1), (-1, 2), (0, -1), (1, -2), (2, 3), (3, -3)}
so j (3) = -3, and
h (g (i (j (f (1))))) = h (g (i (-3)))
And so on. Next you have i (-3) = 2, then g (2) = 0, and finally, h (0) = 0, so your answer is correct.
